3. In Fig. 6.41, if AB DE,
BAC = 35° and
CDE = 53°, find
DCE.
We have,
AB || DE, BAC = 35° and
CDE = 53°
AE is a transversal so, BAC =
AED =
Now, In CDE,
CDE +
DEC +
ECD =
(By angle sum property)
Therefore, ECD =