Q : 5 In Fig., ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that
(v)
[Hint : Join EC and AD. Show that and , etc.]
In right angled triangle ABD, we get
So, in PED,
So,
Therefore, the Area of ..........(i)
And, Area of triangle ...........(ii)
From eq (i) and eq (ii), we get
ar(AFD) = 2. ar(EFD)
Since ar(AFD) = ar(BEF)