Q: 8 In Fig. , ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment meets BC at Y. Show that:
(vii)
We have,
ar(quad. BCDE) = ar(quad, CYXE) + ar(quad. BYXD)
= ar(quad, CYXE) + ar (quad. ABMN) [already proved in part (iii)]
Thus,
Hence proved