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  • In Fig. 9.34, ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment AX ⊥ DE meets BC at Y. Show that: (vii)

Q: 8     In Fig. \small 9.34, ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment \small AX\perp DE  meets BC at Y. Show that:

(vii)    \small ar(BCED)=ar(ABMN)+ar(ACFG)

        

Answers (1)

best_answer


We have,
ar(quad. BCDE) = ar(quad, CYXE) + ar(quad. BYXD)

                           = ar(quad, CYXE) + ar (quad. ABMN)        [already proved in part (iii)]
Thus, \small ar(BCED)=ar(ABMN)+ar(ACFG)

Hence proved

                            

Posted by

manish painkra

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