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3. In Fig 7.33, BD and CE are altitudes of \bigtriangleup ABC such that BD= CE.

          (i) State the three pairs of equal parts in \bigtriangleup CBD and \bigtriangleup BCE.
          (ii) Is \bigtriangleup CBD\cong \bigtriangleup BCE ? Why or why not?
          (iii) Is \angle DCB= \angle EBC ? Why or why not?

                     

Answers (1)

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i) Given,  in \bigtriangleup CBD and \bigtriangleup BCE.

BD= CE

\angle CEB=\angle BDC=90^o 

\overline{ BC} = \overline{ CB}

 

ii) So, By RHS Rule of congruency, we conclude:

\bigtriangleup CBD\cong \bigtriangleup BCE

 

iii) Since both the triangle are congruent, all parts of one triangle are equal to their corresponding part from another triangle.

So.

\bigtriangleup CBD\cong \bigtriangleup BCE.

 

Posted by

Pankaj Sanodiya

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