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Q : 3     In the following APs, find the missing terms in the boxes :

            (ii)   \small \fbox { },\hspace {1mm}13,\hspace{1mm}\fbox { }, \hspace {1mm} 3

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Given AP series is
\small \fbox { },\hspace {1mm}13,\hspace{1mm}\fbox { }, \hspace {1mm} 3
Here, a_2 = 13 , n = 4 \ and \ a_4 = 3
Now,
a_2= a_1+d
a_1= a = 13 - d
Now, we know that
a_n = a+(n-1)d
\Rightarrow a_4 =13-d+(4-1)d
\Rightarrow 3-13=-d+3d
\Rightarrow d = -\frac{10}{2}= -5
Now,
a_2= a_1+d
a_1= a = 13 - d= 13-(-5 ) = 18
And 
a_3=a_2+d
a_3=13-5 = 8
Therefore, missing terms are  18 and 8 
AP series is 18,13,8,3

Posted by

Gautam harsolia

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