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#Mathematics Textbook for Class X
#CBSE 10 Class
#Arithmetic Progressions
#NCERT
#Maths

Q : 3 In the following APs, find the missing terms in the boxes :

(iv) $\small -4,\: \fbox { },\: \fbox { },\: \fbox { },\: \fbox { },\: 6$

Answers (1)

Given AP series is
$\small -4,\: \fbox { },\: \fbox { },\: \fbox { },\: \fbox { },\: 6$
Here, $a = -4 , n = 6 \ and \ a_6 = 6$
Now, we know that
$a_n = a+(n-1)d$
$\Rightarrow a_6 =-4+(6-1)d$
$\Rightarrow 6+4 = 5d$
$\Rightarrow d = \frac{10}{5} = 2$
Now,
$a_2= a_1+d$
$a_2 = -4+2 = -2$
And
$a_3=a_2+d$
$a_3=-2+2 = 0$
And
$a_4 = a_3+d$
$a_4 = 0+2 = 2$
And
$a_5 = a_4 + d$
$a_5 = 2+2 = 4$
Therefore, missing terms are -2,0,2,4
AP series is -4,-2,0,2,4,6