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  • In ∆ ABC, AD is the perpendicular bisector of BC (see Fig). Show that ∆ ABC is an isosceles triangle in which AB = AC.

2. In  \Delta ABC, AD is the perpendicular bisector of BC (see Fig). Show that \small \Delta ABC  is an isosceles triangle in which \small AB=AC.

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Consider \DeltaABD  and  \DeltaADC,

(i)  AD\ =\ AD               (Common in both the triangles)

(ii) \angle ADB\ =\ \angle ADC       (Right angle)

(iii)  BD\ =\ CD             (Since AD is the bisector of BC)

Thus by SAS congruence axiom, we can state :                          \Delta ADB\ \cong \ \Delta ADC

Hence by c.p.c.t., we can say that : \small AB=AC

Thus \Delta ABC is an isosceles triangle with AB and AC as equal sides.

 

Posted by

Devendra Khairwa

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