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Get Answers to all your Questions
Q : 1 In which of the following situations, does the list of numbers involved make an arithmetic progression, and why?
(i) The taxi fare after each km when the fare is for the first km and
for each additional
.
Answers (1)
It is given that
Fare for = Rs. 15
And after that for each additional
Now,
Fare for = Fare of first km + Additional fare for 1 km
= Rs. 15 + 8 = Rs 23
Fare for = Fare of first km + Fare of additional second km + Fare of additional third km
= Rs. 23 + 8= Rs 31
Fare of n km =
( We multiplied by n - 1 because first km was fixed and for rest we are adding additional fare.
In this, each subsequent term is obtained by adding a fixed number (8) to the previous term.)
Now, we can clearly see that this is an A.P. with first term (a) = 15 and common difference (d) = 8
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