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  • In which of the following situations, does the list of numbers involved make an arithmetic progression, and why? (iv) The amount of money in the account every year, when Rs 10000 is deposited at compound interest at 8 percent per annum.

Q : 1     In which of the following situations, does the list of numbers involved make an arithmetic progression, and why?

             (iv) The amount of money in the account every year, when  \small Rs\hspace{1mm}10000  is deposited at  compound interest at  \small 8\hspace{1mm}\%  per annum.

Answers (1)

best_answer

Amount in the beginning = Rs. 10000

Interest at the end of 1st year at rate of \small 8\hspace{1mm}\%
is \small 8\hspace{1mm}\% of 10000 = \frac{8\times 10000}{100}= 800

Therefore, amount at the end of 1st year will be

= 10000 + 800

= 10800

Now,

Interest at the end of 2nd year at rate of \small 8\hspace{1mm}\%
is  \small 8\hspace{1mm}\% of 10800 =\frac{8\times 10800}{100}= 864

Therefore,, amount at the end of 2ndyear

= 10800 + 864 = 11664

Since, each subsequent term is not obtained by adding a unique number to the previous term; hence, it is not an AP

Posted by

Gautam harsolia

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