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Q3  Integrate the functions \frac{1}{x+ x \log x }

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Given to integrate \frac{1}{x+ x \log x } function,

Let us assume 1+\log x = t

we get, \frac{1}{x}dx= dt

\implies \int \frac{1}{x(1+\log x )} dx = \int \frac{1}{t} dt

= \log|t| +C

= \log |1+ \log x | +C   

Posted by

Divya Prakash Singh

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