Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Integrate the functions in Exercises 1 to 9. Root of 4 - x^2

Integrate the functions in Exercises 1 to 9.

    Q1.    \sqrt{4 - x^2}

Answers (1)

best_answer

Given function \sqrt{4 - x^2},

So, let us consider the function to be;

I = \int \sqrt{4-x^2}dx

 = \int \sqrt{(2)^2-x^2}dx

Then it is known that, = \int \sqrt{a^2-x^2}dx =\frac{x}{2}\sqrt{a^2-x^2} +\frac{a^2}{2}\sin^{-1}\frac{x}{a}+C

Therefore, I = \frac{x}{2}\sqrt{4-x^2} +\frac{4}{2}\sin^{-1}{\frac{x}{2}}+C

= \frac{x}{2}\sqrt{4-x^2} +2\sin^{-1}{\frac{x}{2}}+C

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Compartment Result 2026 LIVE: 12th supplementary marksheet soon at cbse.gov.in
anam-khan

CBSE Class 12 Supplementary Exam 2026: 'Chapter-wise weightage ignored,' allege students; seek grace marks
anam-khan

CBSE SARAS 7.0: Affiliation application deadline extended to September 30 for 2027-28 session

Latest Question