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Q 30  Integrate the functions  \frac{\sin x }{1+ \cos x }

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Given function  \frac{\sin x }{1+ \cos x },

Assume the 1+\cos x =t

 \therefore -\sin x dx =dt

\implies \int \frac{\sin x}{1+\cos x}dx = \int -\frac{dt}{t}

= -\log|t| +C

Now, back substituted the value of t.

= -\log|1+\cos x | +C, where C is any constant value.

Posted by

Divya Prakash Singh

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