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4.26     Is there any change in the hybridisation of B and N atoms as a result of the following reaction?

                 BF_{3}+NH_{3}\rightarrow F_{3}B.NH_{3}

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Initially boron atom BF_{3} was in sp^2 hybridised. The valence orbital of boron in the excited state can be shown as:

And nitrogen atom in NH_{3} is sp^3 hybridised. The valence orbital of nitrogen in the excited state can be shown as:

Then after the reaction has occured the product F_{3}B.NH_{3} is formed by the hybridisation of 'B' changes to sp^3. However, the hybridisation of 'N' remains unchanged.

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Divya Prakash Singh

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