Is there any change in the hybridization of B and N atoms as a result of the following reaction?
Initially, the boron atom was in
hybridized. The valence orbital of boron in the excited state can be shown as:
And nitrogen atom in is
hybridized. The valence orbital of nitrogen in the excited state can be shown as:
Then after the reaction has occurred the product $ is formed by the hybridization of 'B' changes to
. However, the hybridization of 'N' remains unchanged.