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Is there any change in the hybridization of B and N atoms as a result of the following reaction?

\mathrm{BF}_3+\mathrm{NH}_3 \rightarrow \mathrm{~F}_3 \mathrm{~B} . \mathrm{NH}_3

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Initially, the boron atom B F_3 was in s p^2 hybridized. The valence orbital of boron in the excited state can be shown as:

And nitrogen atom in \mathrm{NH}_3 is s p^3 hybridized. The valence orbital of nitrogen in the excited state can be shown as:

Then after the reaction has occurred the product F_3 B . N H_3$ is formed by the hybridization of 'B' changes tos p^3. However, the hybridization of 'N' remains unchanged.

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Divya Prakash Singh

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