Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Judge the equivalent resistance when the following are connected in parallel--

Q.   Judge the equivalent resistance when the following are connected in parallel –

             (a)\; 1\; \Omega \; and \; 10^{6}\Omega        (b)\; 1\; \Omega \; and \; 10^{3}\Omega,\; and \; 10^{6}\Omega,

Answers (1)

best_answer

(a)\; 1\; \Omega \; and \; 10^{6}\Omega

    R=Equivalent  resistance

    \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2} 

\Rightarrow \frac{1}{R}=\frac{1}{1}+\frac{1}{10^{6}}

\Rightarrow \frac{1}{R}=\frac{10^6+1}{10^{6}}

\Rightarrow R=\frac{10^6}{10^{6}+1}\approx 1\Omega

(b)\; 1\; \Omega \; and \; 10^{3}\Omega,\; and \; 10^{6}\Omega,

    R=Equivalent  resistance

    \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} 

\Rightarrow \frac{1}{R}=\frac{1}{1}+\frac{1}{10^3}+\frac{1}{10^{6}}

\Rightarrow \frac{1}{R}=\frac{10^6+10^3+1}{10^{6}}

\Rightarrow R=\frac{10^6}{10^{6}+10^3+1}=0.999\Omega \approx 1\Omega

 

 

 

 

 

 

Posted by

seema garhwal

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 Live: CBSE Class 10, 12 board exam timetable soon at cbse.gov.in; practical dates
anam-khan

CBSE Date Sheet 2025 Live: CBSE to announce Class 10, 12 board exam dates soon at cbse.gov.in; sample paper
anam-khan

CBSE Board Exam 2025: Class 10, 12 practical exam dates out at cbse.gov.in; passing marks

Latest Question