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  • Let ABC be a right triangle in which AB equals 6 cm, BC equals 8 cm and angle B equals 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.

6.   Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and \angle B = 90 \degree. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.

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Steps of construction :- 

(i) Draw a line segment BC of length 8 cm.

(ii) Construct a right angle at point B. Now draw a line of length 6 cm. Name the other point as A.

(iii) Join AC. \DeltaABC is the required triangle.

(iv) Now construct a line BD on the line segment AC such that BD is perpendicular to AC.

(v) Now draw a circle taking E as centre (E is midpoint of line BC) and BE as radius.

(vi) Join AE. And draw a perpendicular bisector of this line.

(vii) Name the midpoint of AE as F. 

(viii) Now, draw a circle with F as centre and AF as radius.

(ix) Name the intersection point of both the circles as G.

(x) Join AG. Thus AB and AG are the required tangents.

                                                                   

Posted by

Devendra Khairwa

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