6. Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and B = . BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.
Steps of construction :-
(i) Draw a line segment BC of length 8 cm.
(ii) Construct a right angle at point B. Now draw a line of length 6 cm. Name the other point as A.
(iii) Join AC. ABC is the required triangle.
(iv) Now construct a line BD on the line segment AC such that BD is perpendicular to AC.
(v) Now draw a circle taking E as centre (E is midpoint of line BC) and BE as radius.
(vi) Join AE. And draw a perpendicular bisector of this line.
(vii) Name the midpoint of AE as F.
(viii) Now, draw a circle with F as centre and AF as radius.
(ix) Name the intersection point of both the circles as G.
(x) Join AG. Thus AB and AG are the required tangents.