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Let the resistance of an electrical component remain constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

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By Ohm's law, 

               V=IR

            I=\frac{V}{R}

V=  potential difference

I =current

R = resistance

Now, the potential difference is reduced to half i.e.  

                                                                               V'=\frac{V}{2}

R' = R=resistance

I' =current

I'=\frac{\frac{V}{2}}{R}=\frac{V}{2R}=\frac{I}{2}

The current flow is reduced to half.

Posted by

seema garhwal

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