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  • Line l is the bisector of an angle ∠ A and B is any point on l. BP and BQ are perpendiculars from B to the arms of ∠ A (see Fig. 7.20). Show that: (ii) BP = BQ or B is equidistant from the arms of ∠ A.

5.  Line \small l is the bisector of an angle \small \angle A and \small B  is any point on \small l. \small BP and \small BQ are perpendiculars from \small B to the arms of \small \angle A (see Fig. ). Show that: \small BP=BQ or \small B is equidistant from the arms of  \small \angle A.    

 

Answers (1)

best_answer

In the previous part we have proved that    \small \Delta APB\cong \Delta AQB.

Thus by c.p.c.t. we can write :   BP\ =\ BQ

Thus B is equidistant from arms of angle A.

Posted by

Devendra Khairwa

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