Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.

Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.

Column I Column II
(i) \text {CH}_{3}-\text {O}-\text {CH}_{3} (a)
(ii) (b)
(iii) (c)
(iv) (d) \text {CH}_{3}-\text {OH+CH}_{3}-\text {I}
    (e)
    (f)
    (g)

 

Answers (1)

When the given compounds are reacted with HI, their correct product formation is –(i \rightarrow d), (ii \rightarrow e), (iii \rightarrow b), (iv \rightarrow a)

(i) Due to the symmetrical structure of \text {CH}_{3}-\text {O}-\text {CH}_{3}, the end products of the reaction are \text {CH}_{3}\text {I} and \text {CH}_{2}\text {OH}.
(ii) The compound being asymmetrical follows the SN^{2} mechanism; therefore it forms the following product

(iii) The alkyl group attached to the compound are primary and tertiary; thus, it follows the SN^{1} mechanism. In the process, the halide group attacks the tertiary and forms \left ( \text {CH}_{3} \right )_{3}\text {C-I} and \text {CH}_{3}\text {OH}  

(iv) The structure mentioned is alkyl aryl ether which is an asymmetrical ether in nature. And having the partial bond structure, the products formed are \text {C}_{6}\text {H}_{5}-\text {OH} and \text {CH}_{3}\text {I}.

Posted by

infoexpert23

View full answer

Similar Questions

Latest Question