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  • Multiply and reduce to lowest form (if possible):

2. Multiply and reduce to lowest form (if possible) :

      (i) \; \frac{2}{3}\times 2\frac{2}{3} \; \; \; (ii) \frac{2}{7}\times \frac{7}{9}\; \; \; \; \; (iii)\frac{3}{8}\times \frac{6}{4}\; \; \; \;

       (iv)\; \; \frac{9}{5}\times \frac{3}{5}\; \; \; \; \; (v)\frac{1}{3}\times \frac{15}{8}\; \; \; (vi)\; \; \frac{11}{2}\times \frac{3}{10} \; \; \; (vii)\; \; \frac{4}{5}\times \frac{12}{7}

            

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As we Know, in the multiplication of fraction, the numerator gets multiplied with numerator and denominator gets multiplied by the denominator. So,

\\(i) \; \frac{2}{3}\times 2\frac{2}{3}=\frac{2}{3}\times\frac{8}{3}=\frac{2\times8}{3\times3}=\frac{16}{9}=1\frac{7}{9} \; \; \;\\\\ (ii) \frac{2}{7}\times \frac{7}{9}=\frac{2\times7}{7\times9}=\frac{2}{9}\; \; \; \; \;\\\\ (iii)\frac{3}{8}\times \frac{6}{4}=\frac{3\times6}{8\times4}=\frac{18}{32}=\frac{9}{16}\; \; \; \;

\\(iv)\; \; \frac{9}{5}\times \frac{3}{5}=\frac{9\times3}{5\times5}=\frac{27}{25}=1\frac{2}{25} \\\\ (v)\frac{1}{3}\times \frac{15}{8}=\frac{1\times15}{3\times8}=\frac{15}{24}=\frac{5}{8}\; \; \; \\\\ (vi)\; \; \frac{11}{2}\times \frac{3}{10}=\frac{11\times3}{2\times10}=\frac{33}{20}=1\frac{13}{20} \; \; \; \\\\ (vii)\; \; \frac{4}{5}\times \frac{12}{7}=\frac{4\times12}{5\times7}=\frac{48}{35}=1\frac{13}{35}.

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Pankaj Sanodiya

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