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Q : 1        Multiply the binomials. 

               (i) \small (2x+5)  and  \small (4x-3)

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We have    (2x + 5) and (4x - 3)
    (2x + 5)  X   (4x - 3)   =  (2x)(4x) + (2x)(-3) + (5)(4x) + (5)(-3)
                                       = 8x^{2} - 6x + 20x - 15
                                       = 8x^{2} + 14x -15

Posted by

Gautam harsolia

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