Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Nalorphene (C_19H_21NO_3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 - 10^-3 m aqueous solution required for the above dose.

2.29    Nalorphene (C_{19}H_{21}NO_{3}), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 \; mg. Calculate the mass of 1.5 -10^{-3} m aqueous solution required for the above dose.

Answers (1)

best_answer

We are given with molality of the solution, so we need to find the moles of Nalorphene.

Molar mass of nalorphene =  19(12) + 21(1)  + 1(14) + 3(16)  =  311u.

So moles of nalorphene :

                                             \frac{1.5\times10^{-3}}{311} = 4.82\times 10^{-6}\ moles

Molality :

                                                          = \frac{No.\ of\ moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

or                                                       1.5\times 10^{-3} = \frac{4.82\times 10^{-6}}{w}

or                                                               w = 3.2\times 10^{-3}\ Kg

So the required weight of water is 3.2 g.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question