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  • [NiCl_{4}]^{2-}is paramagnetic while [Ni(CO)_{4}] is diamagnetic though both are tetrahedral. Why?

9.6     [NiCl_{4}]^{2-}is paramagnetic while [Ni(CO)_{4}] is diamagnetic though both are tetrahedral. Why?

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The difference in the magnetic behaviour is due to the nature of ligands present. In case of  [NiCl_{4}]^{2-}  the oxidation state of nickel is +2 and also Cl- is a weak ligand. Thus its configuration becomes:- 

                                                       

So it is paramagnetic and tetrahedral in nature.

In the case of   [Ni(CO)_{4}] ,  the oxidation state of nickel is 0. So its configuration is 3d8 4s2. We also know that CO is a strong ligand, thus the configuration of nickel becomes:-

                                        

Hence the given compound is diamagnetic but tetrahedral in nature.

Posted by

Devendra Khairwa

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