Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Niobium crystallises in body centred cubic structure. If density is 8.55 g cm^-3,calculate atomic radius of niobium using its atomic mass 93u.

1.13   Niobium crystallises in body-centred cubic structure. If density is 8.55\; g\; cm^{-3}, calculate atomic radius of niobium using its atomic mass 93 u.

Answers (1)

best_answer

Here we will use the relation between density and edge length.

                                          Density = \frac{z.M}{a^3.N_A}

It is given that Niobium crystallises in body-centred cubic structure so the value of z = 2.

So we will put the value of density, molar mass and z.

We get,                            

                                          8.55 = \frac{2\times93}{a^3\times6.022 \times10^{23}}

or                                       a^3 = 36.124 \times10^{-24}

or                                       a = 3.3057 \times10^{-8}\ cm

We know the relation between the radius of the atom and edge length in bcc lattice.

                                          r = \frac{\sqrt{3}a}{4}

we get the radius of niobium atom    = 143.1 pm.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date Sheet 2025: CBSE, UPMSP, MPBSE, Class 10, 12 board exam dates out; BSEB, CGBSE schedules soon
anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers
anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4

Latest Question