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On addition of conc. \text {H}_{2}\text {SO}_{4} to a chloride salt, colourless fumes are evolved but in case of an iodide salt, violet fumes come out. This is because

(i) \text {H}_{2}\text {SO}_{4} reduces \text {HI to I}_{2}

(ii) \text {HI} is of violet colour

(iii) \text {HI} gets oxidised to \text {I}_{2}

(iv) \text {HI} changes to \text {HIO}_{3}

Answers (1)

The answer is the option (iii). When concentrated \text {H}_{2}\text {SO}_{4} is added to iodine salt, HI, which is a strong reducing agent, is formed. During the reaction, it is oxidized to \text {I}_{2} , which is violet in colour.

\text {2NaCl + H}_{2}\text {SO}_{4}\rightarrow \text {Na}_{2}\text {SO}_{4}+\text {2HCl}

In case of iodine the halogen acid \text {HI} obtained reduces \text {H}_{2}\text {SO}_{4} to \text {SO}_{2} and  itself is oxidised to free iodine.

\text {2NaI + H}_{2}\text {SO}_{4}\rightarrow \text {Na}_{2}\text {SO}_{4}+ \text {2HI}\overset{\text {H}_{2}\text {SO}_{4}}{\rightarrow} \text {2H}_{2}\text {O + SO}_{2}+\text {I}_{2}

 

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