Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is : (iv) 0

Q5.4 One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is :

(i)    T

(ii)    T - \frac{mv^2}{l}

(iii)    T + \frac{mv^2}{l}

(iv)    0

T is the tension in the string. [Choose the correct alternative].

Answers (1)

best_answer

When the particle is moving in a circular path, the centripetal force will be :

                                                              F_c\ =\ \frac{mv^2}{r}

This centripetal force will be balanced by the tension in the string.

So,  the net force acting is :   

                                                     F\ =\ T\ =\ \frac{mv^2}{r} 

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE date sheet 2025 for Classes 10, 12 likely in November last week: Reports
anam-khan

CBSE allows Class 10, 12 students from disaffiliated schools to appear for board exam 2025 from same school
anam-khan

CBSE withdraws affiliation of 21 schools, downgrades 6 schools in two states; most in Delhi

Latest Question