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  • One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be (A) 10x + 14y + 4 = 0 (B) –10x – 14y + 4 = 0 (C) –10x + 14y + 4 = 0 (D) 10x – 14y = –4

One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be
(A) 10x + 14y + 4 = 0
(B) –10x – 14y + 4 = 0
(C) –10x + 14y + 4 = 0
(D) 10x – 14y = –4

Answers (1)

Answer: D
Solution:
Given equation is
–5x + 7y – 2 = 0
a1 = –5, b1 = 7, c1 = –2
For dependent linear equation
\frac{a_{1}}{a_{2}}= \frac{b_{1}}{b_{2}}= \frac{c_{1}}{c_{2}}= \frac{1}{k}
\frac{-5}{a_{2}}= \frac{7}{b_{2}}= \frac{-2}{c_{2}}= \frac{1}{k}          
a2 = –5k, b2 = 7k, c2 = –2k
Put k = 2
a2 = –10, b2 = 14, c2 = –4
The revived equation is of the type a2x + b2y + c2 = 0
Put a2 = – 10, b2 = 14, c2= –4
–10x + 14y – 4 = 0
10x – 14 y = –4

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