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Q. 3.     Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.

            (a) $5m=60$                      $(10,5,12,15)$

            (b) $n+12=20$              $(12,8,20,0)$

             (c) $p-5=5$                 $(0,10,5,-5)$

             (d) $\frac{q}{2}=7$                          $(7,2,10,14)$

             (e) $r-4=0$               $(4,-4,8,0)$

            (f) $x+4=2$                      $(-2,0,2,4)$

Answers (1)

best_answer

(a) $5m=60$

Putting given values in LHS.

$5\times 10=50$ $5\times 12=60$

$\therefore LHS\neq RHS$ $\therefore LHS= RHS$

m = 10 is not a solution. m = 12 is a solution.

$5\times 5=50$ $5\times 15=75$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

m = 5 is not a solution. m = 15 is not a solution.

(b) $n+12=20$

Putting given values in LHS.

$12+12=24$ $20+12=32$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

n = 12 is not a solution. n = 20 is not a solution.

$8+12=20$ $0+12=12$

$\therefore LHS= RHS$ $\therefore LHS\neq RHS$

n = 8 is a solution. n =0 is not a solution.

(c) $p-5=5$

Putting given values in LHS.

$0-5=-5$ $10-5=5$

$\therefore LHS\neq RHS$ $\therefore LHS= RHS$

p =0 is not a solution. p = 10 is a solution.

$5-5=0$ $-5-5=-10$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

p = 5 is not a solution. p = -5 is not a solution

(d) $\frac{q}{2}=7$

Putting given values in LHS.

$\frac{7}{2}$ $\frac{2}{2}=1$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

q =7 is not a solution. q = 2 is not a solution.

$\frac{10}{2}=5$ $\frac{14}{2}=7$

$\therefore LHS\neq RHS$ $\therefore LHS= RHS$

q = 10 is not a solution. q = 14 is a solution.

(e) $r-4=0$

Putting given values in LHS.

$4-4=0$ $-4-4=-8$

$\therefore LHS= RHS$ $\therefore LHS\neq RHS$

r =4 is a solution. r = -4 is not a solution.

$8-4=4$ $0-4=-4$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

r = 8 is not a solution. r = 0 is not a solution

(f) $x+4=2$

Putting given values in LHS.

$-2+4=2$ $0+4=4$

$\therefore LHS= RHS$ $\therefore LHS\neq RHS$

x = -2 is a solution. x = 0 is a solution.

$2+4=6$ $4+4=8$

$\therefore LHS\neq RHS$ $\therefore LHS\neq RHS$

x = 2 is not a solution. x = 4 is not a solution

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