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8.27 Predict the products of electrolysis in each of the following:

(i) An aqueous solution of AgNO_{3} with silver electrodes 

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Answer- 

(i) AgNO_{3} dissociate into Ag^{+} and NO_{3}^{-}

@ CathodeAg^{+}(aq)+e^{-}\rightarrow Ag(s) (reduction potential of silver is higher than H_{2}OE^{0} = 0.80V

@Anode - Ag(s)\rightarrow Ag^{+}(aq)+e^{-} (oxidation potential of silver is higher than water molecule.So silver electrode oxidized )E^{0} = -0.83V

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Gautam harsolia

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