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3.18     Predict the products of electrolysis in each of the following:

                (iii) A dilute solution of H_{2}SO_{4} with platinum electrodes.

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For the given solution :

 At cathode :-    Reaction with greater E0 will take place.

                                     H^+\ +\ e^-\ =\ \frac{1}{2}H_2_{(g)}

At anode :-     Self ionisation of water will take place due to presence of platinum electrode.

                               H_2O\ \rightarrow\ 2H^+\ + \frac{1}{2}O_2\ +\ 2e^-

Hence, H2 gas will be generated at cathode and O2 will be produced from anode.

                                    

Posted by

Devendra Khairwa

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