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Get Answers to all your Questions
Q 5. Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonals.
Answers (1)
Given : ABCD is rhombus.
To prove : the circle drawn with AB as diameter, passes through the point O.
Proof :
ABCD is a rhombus.
Thus, $\angle A O B=90^{\circ} \quad$ (diagonals of a rhombus bisect each other at $90^{\circ}$ )
So, a circle drawn AB as diameter will pass through point O .
Thus, the circle is drawn with any side of a rhombus as the diameter passes through the point of intersection of its diagonals.
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