Get Answers to all your Questions

header-bg qa

5.   Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.

Answers (1)

best_answer


In the above figure, the line AXB is the tangent to a circle with centre O. Here, OX is the perpendicular to the tangent AXB (OX\perp AXB) at point of contact X. 
Therefore, we have,
\angleBXO + \angleYXB = 90^0+90^0=180^0

\therefore OXY is a collinear 
\Rightarrow OX is passing through the centre of the circle.

Posted by

manish

View full answer