Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Q4(1)    The function ‘t’ which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(c) = 9C/5 +32

Q4(2)    The function ‘t’ which maps temperature in degree Celsius into temperature in
       degree Fahrenheit is defined by t ( C ) = \frac{9 C }{5} + 32
        t (28) 

Answers (1)

best_answer

Given function is 
t ( C ) = \frac{9 C }{5} + 32
Now,
t ( 28 ) = \frac{9 (28) }{5} + 32= \frac{252}{5}+ 32 = \frac{252+160}{5}= \frac{412}{5}
Therefore,
Value of t(28) is  \frac{412}{5}

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exams 2025: Counselling for students, parents from February 1
anam-khan

CBSE asks schools to include APAAR IDs in school ID after NTA says ‘not mandatory’ for NEET
anam-khan

CBSE Board Exams 2025: What the ethics code bans from exam centres

Latest Question