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  • Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 omega resistor. What would be the readings in the ammeter and the voltmeter?

Question 1:  Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 5 \Omega resistor, an 8 \Omega  resistor, and a 12 \Omegaresistor, and a plug key, all connected in series.

     Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a  voltmeter to measure the potential difference across the 12\; \Omega resistor. What would be the readings in the ammeter and the voltmeter?

Answers (1)

best_answer

The diagram is as shown :

Resistance of circuit =R=5+8+12=25 

Potential = 6V

V=IR

\Rightarrow I=\frac{V}{R}=\frac{6}{25}=0.24A

Now, for 12 ohm resistor, current = 0.24 A.

By Ohm's law,

                      V=IR=0.24\times 12=2.88V

Reading of ammeter is o.24A and voltmeter is 2.88V.

 

 

 

 

 

 

 

Posted by

seema garhwal

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