Question 1: Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a resistor, a resistor, a resistor, and a plug key, all connected in series.
Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the resistor. What would be the readings in the ammeter and the voltmeter?
The diagram is as shown :
Resistance of circuit =R=5+8+12=25
Potential = 6V
Now, for a 12-ohm resistor, current = 0.24 A.
By Ohm's law,
Reading of ammeter is o.24A and voltmeter is 2.88V.