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Q : 2      Reduce the following equations into intercept form and find their intercepts on the axes. 

            (i)  3x+2y-12=0

Answers (1)

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Given equation is
3x+2y-12=0
we can rewrite it as
\frac{3x}{12}+\frac{2y}{12} = 1
\frac{x}{4}+\frac{y}{6} = 1                         -(i)
Now, we know that the intercept form of line is
\frac{x}{a}+\frac{y}{b} = 1                         -(ii)
Where a and b are intercepts on x and y axis respectively
On comparing equation (i) and (ii)
we will get
a = 4 and b = 6
Therefore,  intercepts on x and y axis  are 4 and 6 respectively

Posted by

Gautam harsolia

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