Seven persons are to be seated in a row. The probability that two particular persons sit next to each other is
A. 1/3
B. 1/6
C. 2/7
D. 1/2
7 persons are to be seated in a row ….. (given)
Let us consider 2 persons as 1 group since 2 persons sit next to each other.
Thus, we have to arrange 6 persons.
Thus, the number . of arrangement = 2! X 6!
Thus, total number . of arrangement of 7 persons = 7!
Now,
Probability = number of favourable outcomes/total numbers of outcomes
= 2! X 6! / 7!
= 2 x 1 x 6! / 7 x 6!
= 2/ 7
Thus, option C is the correct answer.