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 Q.11.    Show how you would connect three resistors, each of resistance6\Omega , so that the combination has a resistance of (i) 9\Omega, (ii) 4\Omega .
 

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(i) R_1=R_2=R_3=6

    R=Equivalent  resistance

    \frac{1}{R_1_2}=\frac{1}{R_1}+\frac{1}{R_2} 

\Rightarrow \frac{1}{R_1_2}=\frac{1}{6}+\frac{1}{6}

\Rightarrow \frac{1}{R_1_2}=\frac{1+1}{6}

\Rightarrow R_1_2=\frac{6}{2}=3

R=R_1_2+R_3=3+6=9\Omega

(ii)

.R_1=R_2=R_3=6

  R=Equivalent  resistance

R_1_2=R_1+R_2=6+6=12\Omega

 

  \frac{1}{R}=\frac{1}{R_1_2}+\frac{1}{R_3} 

\Rightarrow \frac{1}{R}=\frac{1}{12}+\frac{1}{6}

\Rightarrow \frac{1}{R}=\frac{1+2}{12}

\Rightarrow R=\frac{12}{3}=4

 

 

 

 

Posted by

seema garhwal

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