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Get Answers to all your Questions
Show that 12n cannot end with the digit 0 or 5 for any natural number n.
Answers (1)
We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5.
Here 12n = (2 × 2 × 3)n
12n = (22 × 3)n
12n = (22n × 3n)
5 is not there, in the prime factorization form.
Hence 12n can’t end with the digit 0 or 5.
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