Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Show that cos 38^o cos 52^o- sin 38^o sin 52^o = 0

2.  Show that :

   (ii) \cos 38^{o}\cos 52^{o}-\sin 38^{o}\sin 52^{o}= 0

Answers (1)

best_answer

\cos 38^{o}\cos 52^{o}-\sin 38^{o}\sin 52^{o}= 0

Taking Left Hand Side (LHS)
=\cos 38^{o}\cos 52^{o}-\sin 38^{o}\sin 52^{o}
=\cos 38^{o}\cos (90^o-38^{o})-\sin 38^{o}\sin (90^o-38^{o})
=\cos 38^{o}\sin38^{o}-\sin 38^{o}\cos 38^{o} [it is known that \sin(90^0-\theta) =\cos \theta and \cos(90^0-\theta) =\sin \theta ]
= 0

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

Board Exams Date Sheet 2025 Live: RBSE 10th, 12th exams from March 6; CBSE admit card expected by month-end

Latest Question