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Show that in a cubic close packed structure, eight tetrahedral voids are present per unit cell.

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In ccp, each unit cell consists of eight cubic components, and the number of atoms per unit cell is given by

Nc*contribution+Nf*contribution  

=8\times \frac{1}{}8+6\times \frac{1}{2}=4
 
The tetrahedral voids are positioned at the center of the cubic cell.

In cubic close packing number of tetrahedral voids per unit cell = 8\times 1=8

A unit cell in a ccp structure is divided into eight smaller cubes, each with four atoms at its alternate corners. When these atoms are joined together, they create a tetrahedral void. Since there are eight smaller cubes in each unit cell, and each smaller cube has one tetrahedral void, there are eight tetrahedral voids in each unit cell.

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