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3 c) Show that the function given by f (x) = \sin x is neither increasing nor decreasing in ( 0 , \pi )

 

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We know that sin x is strictly increasing in \left ( 0,\frac{\pi}{2} \right )   and strictly decreasing in \left ( \frac{\pi}{2},\pi \right )
So, by this, we can say that f(x) = sinx is neither increasing or decreasing in range  \left ( 0,\pi \right )

Posted by

Gautam harsolia

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