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  • Show that the general solution of the differential equation is given by (x + y + 1) = A (1 - x - y - 2xy), where A is parameter.

Q7.    Show that the general solution of the differential equation \frac{dy}{dx} + \frac{y^2 + y + 1}{x^2 + x + 1} = 0 is given by (x + y + 1) = A (1 - x - y - 2xy), where A is parameter.

Answers (1)

best_answer

Given,

\frac{dy}{dx} + \frac{y^2 + y + 1}{x^2 + x + 1} = 0

Integrating both sides,

Let  

Let  A = , 

Hence proved.

Posted by

HARSH KANKARIA

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