2.16 ( a) Show that the normal component of the electrostatic field has a discontinuity from one side of a charged surface to another given by
where nˆ is a unit vector normal to the surface at a point and σ is the surface charge density at that point. Hence, show that just outside a conductor, the electric field is
The electric field on one side of Surface with charge density
The electric field on another side of Surface with charge density
Now, resultant of both surfaces:
As E1 and E2 are opposite in direction. we have
There has to be a discontinuity at the sheet of the charge since both electric fields are in the opposite direction.
Now,
Since the electric field is zero inside the conductor,
the electric field just outside the conductor is