Simplify and solve the following linear equation.
Q.9 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17
Let us open the brackets.
LHS: 3(5z - 7) - 2(9z - 11)
= 15z - 21 - 18z + 22
= -3z + 1
RHS: 4(8z - 13) - 17
= 32z - 52 - 17
= 32z - 69
So the equation becomes : -3z + 1 = 32z - 69
or 69 + 1 = 32z + 3z
or 70 = 35z
z = 2