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Q1.    Solve 24x< 100, when

                (ii) x is an integer.

Answers (1)

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Given :   24x < 100

\Rightarrow      24x < 100

Divide by 24 from both sides 

\Rightarrow \, \, \, \frac{24}{24}x< \frac{100}{24}

   \Rightarrow \, \, \, x< \frac{25}{6}

\Rightarrow \, \, \, x< 4.167

 

x is are integers which are less than 4.167.

Hence, values of x can be \left \{..........-3,-2,-1,0, 1,2,3,4 \right \}

Posted by

seema garhwal

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