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  • Solve each of the following equations: (2) 2x^2+x+1=0

Solve each of the following equations: 

Q: 2        2x^2+x+1=0

Answers (1)

best_answer

Given equation is
2x^2+x+1=0 
Now, we know that the roots of the quadratic equation are given by the formula
\frac{-b\pm \sqrt{b^2-4ac}}{2a}
In this case value of a = 2 , b = 1 and c = 1
Therefore,
\frac{-1\pm \sqrt{1^2-4.2.1}}{2.2}= \frac{-1\pm\sqrt{1-8}}{4} = \frac{-1\pm\sqrt{-7}}{4}=\frac{-1\pm\sqrt7i}{4}
Therefore, the solutions of requires equation are 

 \frac{-1\pm\sqrt7i}{4}

Posted by

Gautam harsolia

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