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  • Solve for x the inequalities in 4/x+1 < 3< 6/x+1, (x>0)

Solve for x the inequalities in \frac{4}{x+1}\leq 3\leq \frac{6}{x+1},\left ( x> 0 \right )

Answers (1)

Given:  \frac{4}{x+1}\leq 3\leq \frac{6}{x+1},\left ( x> 0 \right )

Now, let us multiply all the terms by \left ( x+1 \right ), we get,

4\leq 3\left ( x+1 \right )\leq 6

i.e.,  4\leq 3x+3 \leq 6

Now, on subtracting each term by 3, we get,

1\leq 3x\leq 3

At last, we will divide each term by 3,

We get,

\left ( 1/3 \right )\leq x\leq 1


 

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infoexpert22

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