Solve the following equation and check your result.
Q.4 4z + 3 = 6 + 2z
We have
4z + 3 = 6 +2z
Transposing 2z to the LHS and 3 to the RHS, we get:
4z - 2z = 6 - 3
or 2z = 3
DIviding both sides by 2,
Check:- Put in LHS as well as RHS, we have
LHS :- 4z + 3
RHS :- 6 + 2z
Thus, LHS = RHS
3x=2x+18
3x-2x=18
x=18
equation substitute x=18 in l.h.< r.h.s
3(18)=2(18)+18
54=36+18
54=54
LHS=RHS
=