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Solve the inequality for real x

    Q11.    \frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}

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Given :   \frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}

\Rightarrow      \frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}

\Rightarrow \, \, \, 9(x-2)\leq 25(2-x)

\Rightarrow \, \, \, 9x-18\leq 50-25x

 \Rightarrow \, \, \, 9x+25x\leq 50+18

\Rightarrow \, \, \, 34x\leq 68

\Rightarrow \, \, \, x\leq 2

x are  real numbers less than equal to 2.

Hence, values of x can be  as  x\in (-\infty ,2]

Posted by

seema garhwal

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