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Solve the inequality for real x

    Q9.    x + \frac{x}{2} + \frac{x}{3} < 11

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Given :   x + \frac{x}{2} + \frac{x}{3} < 11

\Rightarrow      x + \frac{x}{2} + \frac{x}{3} < 11

\Rightarrow \, \, \, x(1+\frac{1}{2}+\frac{1}{3})< 11

\Rightarrow \, \, \, x(\frac{11}{6})< 11

 \Rightarrow \, \, \, 11 x< 11\times 6

\Rightarrow \, \, \, x< 6

x are  real numbers less than 6

Hence, values of x can be  as  x\in (-\infty ,6)

Posted by

seema garhwal

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