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State whether the statements are True or False.

The probabilities that a typist will make 0, 1, 2, 3, 4, 5 or more mistakes in typing a report are, respectively, 0.12, 0.25, 0.36, 0.14, 0.08, 0.11.

Answers (1)

Let us consider that –

A → event that typist will make 0 mistake

B → event that typist will make 1 mistake

C → event that typist will make 2 mistake

D → event that typist will make 3 mistake

E → event that typist will make 4 mistake

F → event that typist will make 5 mistake

We have,

P (A) = 0.12

P (B) = 0.25

P (C) = 0.36

P (D) = 0.14

P (E) = 0.08

P (F) = 0.11

Now,

Sum of all probabilities = 1

Thus,

P (A) + P (B) + P (C) + P (D) + P (E) + P (F)

= 0.12 + 0.25 + 0.36 + 0.14 + 0.08 + 0.11

= 1.06 viz. > 1

Thus, the given statement is False.

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